{"id":5056,"date":"2021-12-04T17:20:04","date_gmt":"2021-12-04T16:20:04","guid":{"rendered":"https:\/\/www2.ual.es\/neotrie\/?p=5056"},"modified":"2026-05-27T11:46:43","modified_gmt":"2026-05-27T10:46:43","slug":"espiral-pitagorica","status":"publish","type":"post","link":"https:\/\/www2.ual.es\/neotrie\/espiral-pitagorica\/","title":{"rendered":"Espiral pitag\u00f3rica"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">En esta actividad, disponible en la caja de Erasmus Geometrician's Views, realizamos una espiral pitag\u00f3rica en el espacio con las herramientas de perpendicularidad y comp\u00e1s. La construcci\u00f3n es din\u00e1mica y podemos modificar algunos par\u00e1metros. A diferencia de la construcci\u00f3n en el plano, esta es m\u00e1s compleja, por no haber una \u00fanica perpendicular a una recta en el espacio.<\/p>\n\n\n\n<figure class=\"wp-block-video\"><video controls src=\"https:\/\/www2.ual.es\/neotrie\/wp-content\/uploads\/2021\/12\/YouCut_20211204_193345672.mp4\"><\/video><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">A continuaci\u00f3n podemos ver c\u00f3mo se ha hecho:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www2.ual.es\/neotrie\/wp-content\/uploads\/2022\/08\/301205444_10226479429187341_1981788925199990284_n.jpg\" alt=\"\" class=\"wp-image-6255\" width=\"359\" height=\"359\"\/><figcaption>Construcci\u00f3n de tri\u00e1ngulos rect\u00e1ngulos consecutivos para la espiral pitag\u00f3rica. Tambi\u00e9n puede usarse el modo \"Plane geometry\" para simplificar.<\/figcaption><\/figure>\n\n\n\n<ol class=\"wp-block-list\"><li>Empezamos con 3 puntos A, B, C.<\/li><li>Aparte, hacemos el segmento PQ que nos fijar\u00e1 la longitud del lado menor de todos los tri\u00e1ngulos rect\u00e1ngulos de la espiral.<\/li><li>Con la herramienta perpendicular tocamos los v\u00e9rtices A, B, C para obtener un v\u00e9rtice D que nos dar\u00e1 la direcci\u00f3n perpendicular a dicho plano en B.<\/li><li>Tocamos A, B, D, para obtener un v\u00e9rtice E perpendicular a la arista AB, contenida en el plano ABC.<\/li><li>Con la herramienta comp\u00e1s (modo 0), tocamos P, Q, B, E. Eso nos dar\u00e1 un v\u00e9rtice F, tal que ABF es el tri\u00e1ngulo rect\u00e1ngulo deseado.<\/li><li>Realizamos el tri\u00e1ngulo ABF con el modo cara (tri\u00e1ngulo) de la mano.<\/li><li>Para facilitar la construcci\u00f3n de las siguientes perpendiculares, todas ellas contenidas en el plano ABC, o ABF (que es el mismo), elegimos la opci\u00f3n \"Plane geometry\" en la herramienta de perpendiculares y tocamos el plano ABF. <\/li><li>Tocamos con la herramienta de perpendiculares el v\u00e9rtice F y la arista AF para dar un nuevo v\u00e9rtice G y seguir la construcci\u00f3n indicada en el siguiente video para construir el tri\u00e1ngulo AFH.<\/li><\/ol>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-4-3 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Pythagorean spiral\" width=\"1080\" height=\"810\" src=\"https:\/\/www.youtube.com\/embed\/M3Glj4PcLco?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<figure class=\"wp-block-video\"><video controls src=\"https:\/\/www2.ual.es\/neotrie\/wp-content\/uploads\/2022\/08\/YouCut_20220826_112801434.mp4\"><\/video><figcaption>Uso de la opci\u00f3n \"Plane Geometry\" de la herramienta de perpendiculares.<\/figcaption><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Sigue el hilo de esta actividad en <a href=\"https:\/\/twitter.com\/NatalijaNovta\/status\/1466884114733322247\">Twitter<\/a>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www2.ual.es\/neotrie\/wp-content\/uploads\/2022\/01\/FFtrAl1XIAglMIL-2-721x1024.jpg\" alt=\"\" class=\"wp-image-5301\" width=\"322\" height=\"457\"\/><figcaption>Dise\u00f1os de alumnado de Natalija Budinski.<\/figcaption><\/figure>\n\n\n\n<div class=\"wp-block-group is-layout-flow wp-block-group-is-layout-flow\">\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www2.ual.es\/neotrie\/wp-content\/uploads\/2021\/08\/logo-GEOM-1024x695.png\" alt=\"\" class=\"wp-image-4747\" width=\"197\" height=\"134\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www2.ual.es\/neotrie\/wp-content\/uploads\/2021\/12\/descarga-2-1024x223.png\" alt=\"\" class=\"wp-image-5098\" width=\"221\" height=\"47\"\/><\/figure>\n<\/div>\n","protected":false},"excerpt":{"rendered":"","protected":false},"author":3,"featured_media":5057,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[11],"tags":[140],"class_list":["post-5056","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-secundaria","tag-espirales"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 4.9.8 - aioseo.com -->\n\t<meta name=\"description\" content=\"En esta actividad, disponible en la caja de Erasmus Geometrician&#039;s Views, realizamos una espiral pitag\u00f3rica en el espacio con las herramientas de perpendicularidad y comp\u00e1s. 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